Silent Duelsвђ”constructing The Solution Part 2 Вђ“ Math В€© Programming May 2026

import numpy as np from scipy.integrate import quad def construct_strategy(accuracy_func, derivative_func): # 1. Find the starting threshold 'a' # For a symmetric 1-bullet duel, a is found where # the integral of f(x) from a to 1 equals 1. def integrand(x): return derivative_func(x) / (accuracy_func(x)**3) # We solve for 'a' such that integral equals 1/h # (Simplified for demonstration) a = 0.33 # Derived from solving the integral for A(x)=x return lambda x: integrand(x) if x >= a else 0 # Example: Linear Accuracy A(x) = x f_optimal = construct_strategy(lambda x: x, lambda x: 1) Use code with caution. Copied to clipboard 4. Programming Challenges: Precision and Normalization

Should we look at the for solving the threshold when the accuracy function is complex? import numpy as np from scipy

, but real-world simulations might use a sigmoid or exponential curve. Copied to clipboard 4

While the math is continuous, a game engine or simulation usually runs on discrete ticks. You must normalize the PDF so that the sum of probabilities across all frames equals 1. 5. Summary of the Construction To build the solution: Define : How likely are you to hit at time Calculate the Threshold : The point where "waiting" becomes statistically viable. Generate the PDF : Use the derived to distribute firing chances. While the math is continuous, a game engine

For a symmetric duel (equal accuracy and one bullet each), the boundary condition is: ∫a1f(x)dx=1integral from a to 1 of f of x d x equals 1 2. Solving the Integral Equation

In a silent duel, the core challenge is that neither player knows when the other has fired. This lack of information forces us to rely on a rather than a single "best" time to shoot. 1. The Strategy Profile To construct the solution, we define a strategy as a distribution of firing times. If is the probability of hitting the target at time

In Part 3, we will look at , where one player is more accurate or has more bullets than the other.